Question

Find out the number of elections, protons and neutron
following
40Ar
18​

Answer 1

Answer:-

• The element is Argon here.

The symbol given by

$\\ \sf\longmapsto 18^{Ar^{40}}$

Here

• Atomic mass=40
• Atomic number=18

We know

$\\ \sf\longmapsto No\:of\:protons=Atomic\:Number$

$\therefore\underline{\boxed{\bf No\:of\:Protons=18}}$

Again

$\\ \sf\longmapsto No\:of\:protons=No\:of\:electrons$

$\therefore\underline{\boxed{\bf No\:of\:electrons=18}}$

And

$\\ \sf\longmapsto No\:of\:Neutrons=Atomic\:Mass-No\:of\:Protons$

$\\ \sf\longmapsto 40-18=22$

$\therefore\underline{\boxed{\bf No\:of\:Neutrons=22}}$