Question

Find out the number of electrons, protons and neutrons in 2.7g of Al3+ ion??​

Answer 1

Answer:

Number of moles of 9g of Al3+ ion = 9/27(given mass/molar mass)

Now, number of ions of Al3 = 1/3*6.022*10^23=2.007*10^23(number of ions/atoms/molecules=Avogadro's number*number of moles)

Now, number of electrons in 1 ion of Al3+ = 10

So, 2.007*10^23 ions will have 2.007*10^23*10 = 2.007*10^24 electrons.