Question

find out the number of molecules of 500g caco3 ca=40 c=12 o= 16​

Answer 1

Answer:

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Answer 2

Explanation:

No. of moles = given mass of compound / Molar mass

Given mass = 500g

Molar mass = (40 + 12 + 3x16) =100g/mol

No of moles of CaCO3 = 500 / 100 = 5 mol

According to Avogadro’s law –

1 mol of CaCO3 molecules contains 6.022 x 1023 CaCO3 molecules

Hence, 5 mol of CaCO3 molecules will contain 6.022 x 1023x 5 molecules

i.e. 3080.253 molecules