Chemistry, asked by karan23422, 9 months ago

Find out the number of waves made by a Bohr electron in its 3rd orbit.​

Answers

Answered by nprakash28
0

Answer:

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Explanation:

In general, the number of waves made by a Bohr electron in an orbit is equal to its quantum number. Thus the circumference of the 3rd orbit is equal to 3 times the wavelength of electron i.e. the electron makes three revolution around the 3rd orbit.

Answered by siddhantprasad8
0

No. of waves made by Bohr electron in one complete rotation = \frac{2\pi r } {λ} (λ=λ)

∵ mvr = \frac{nh}{2\pi }

∴ 2πr = \frac{nh}{mv} = nλ .... ( ∵ λ = \frac{h}{mv} )

\frac{2\pi r } {λ} (λ=λ) = n

∴ no. of waves = n = 3   [n=3 for required orbit.]

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