Question

Find out the oxidation number of chromium in potassium dichromate and

chlorine in potassium chlorate.​

Answer 1

Answer:

Let, X be the oxidation state of Cr in K  

2

​  

Cr  

2

​  

O  

7

​  

.

2(+1)+2X+7(−2)=0

2+2X−14=0

2X=12

X=+6

Hence, the oxidation state of Cr in K  

2

​  

Cr  

2

​  

O  

7

​  

 is +6.

Explanation:

Answer 2

Answer:

So from that, you can work out that to balance out the single potassium (+1) and three oxygens (-2 each), the chlorine has to have an oxidation number of +5 (1+5 -6 = 0).