Question

Find out the oxidation state of sodium in $Na_{2}O_{2}$.

Answer 1

1) Diatomic molecules like ${ H }_{ 2 },\quad { Cl }_{ 2 }........$ have zero oxidation state.

2) The "oxidation number" of a "mono atomic" ion is equal to the charge present in the ion.

3) "Sum" of all "oxidation numbers" in a "neutral compound" is equal to value "zero".

4) "Alkaline metal" have +1 oxidation number and "alkaline earth metals" have +2 oxidation number.

5) Oxygen has -2 oxidation state but the oxidation number of oxygen in peroxide form is -1.  

6) Oxidation number is Hydrogen is -1 but in binary metal hydride oxidation number of hydrogen is +1.

7) Oxidation number of halide are always -1, unless they are in combination with an oxygen or fluorine.

Let the oxidation state of Na be x.

The oxidation state of oxygen, in case of peroxides, is -1

Therefore,

$2(x)\quad +\quad 2(-1)\quad =\quad 0$

$2x\quad -\quad 2\quad =\quad 0\\ 2x\quad =\quad 2$

$x\quad =\quad 1$

Therefore, the "oxidation state" of "sodium" is +1.

Answer 2

heya...!!!

✔here is ua answer:
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1) Diatomic molecules like { H }_{ 2 },\quad { Cl }_{ 2 }........H2​,Cl2​........ have zero oxidation state.

2) The "oxidation number" of a "mono atomic" ion is equal to the charge present in the ion.

3) "Sum" of all "oxidation numbers" in a "neutral compound" is equal to value "zero".

4) "Alkaline metal" have +1 oxidation number and "alkaline earth metals" have +2 oxidation number.

5) Oxygen has -2 oxidation state but the oxidation number of oxygen in peroxide form is -1.  

6) Oxidation number is Hydrogen is -1 but in binary metal hydride oxidation number of hydrogen is +1.

7) Oxidation number of halide are always -1, unless they are in combination with an oxygen or fluorine.

Let the oxidation state of Na be x.

The oxidation state of oxygen, in case of peroxides, is -1

Therefore,

2(x)\quad +\quad 2(-1)\quad =\quad 02(x)+2(−1)=0

\begin{lgathered}2x\quad -\quad 2\quad =\quad 0\\ 2x\quad =\quad 2\end{lgathered}2x−2=02x=2​

x\quad =\quad 1x=1

Therefore, the "oxidation state" of "sodium" is +1.

hope it helps..!!!❤