Find out the parcent composition of sulphur and hydrogen in H2SO4
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molar mass of H2SO4 = 2(1) + 32 + 4(16) = 98 g
mass of H = 2 mol H x 1.008g/mol = 2.016 g
mass of S = 1 mol S x 32.00g /mol = 32.00 g
mass of O = 4 mol O x 16.00g/mol = 64.00 g
mass % H = 2.016g/98g x 100 = 2.06%
mass % S = 32.00g/98g x 100 = 32.6%
mass % O = 64.00g/98g x 100 = 65.3%
mass of H = 2 mol H x 1.008g/mol = 2.016 g
mass of S = 1 mol S x 32.00g /mol = 32.00 g
mass of O = 4 mol O x 16.00g/mol = 64.00 g
mass % H = 2.016g/98g x 100 = 2.06%
mass % S = 32.00g/98g x 100 = 32.6%
mass % O = 64.00g/98g x 100 = 65.3%
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