Find out the percentage composition of each element present in Sulphuric acid .
help me fast !!
Answers
Answered by
37
HELLO DEAR,
MASS OF THE COMPOSITION
=MASS OF THE COMPONENTS) / TOTAL MASS OF COMPOUNDS)×100
HERE,
MASS Of S-ATOM = 32 gm and IN H2SO4 ONLY ONE
S-Atom IS PRESENT.
FURTHER MOLAR MASS Of H2SO4 = 2 + 32+ 64 = 98 gm
HENCE, PERCENTAGE OF Sulphur = (32/98) x 100 = 32.65 %
I HOPE ITS HELP YOU DEAR,
THANKS
MASS OF THE COMPOSITION
=MASS OF THE COMPONENTS) / TOTAL MASS OF COMPOUNDS)×100
HERE,
MASS Of S-ATOM = 32 gm and IN H2SO4 ONLY ONE
S-Atom IS PRESENT.
FURTHER MOLAR MASS Of H2SO4 = 2 + 32+ 64 = 98 gm
HENCE, PERCENTAGE OF Sulphur = (32/98) x 100 = 32.65 %
I HOPE ITS HELP YOU DEAR,
THANKS
Similar questions