Question

find out the percentage of oxalate in the sample of oxalate salt in which 0.3 gram dissolved in 100 ml of water required 90 ml of 1\20 normal kmno4 for complete oxidation

Answer 1

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Answer 2

Hello dear,

● Answer -
Percentage of oxalate ions in salt = 66 %

● Explaination -
When oxalate salt is dissolved in water -
(C2O4)-- → 2CO2 + 2e-


Let x be weight of oxalate ions in salt.

As solution is completely oxidized with KMnO4,
Meq(Oxalate) = Meq(KMnO4)
x / (88/2) × 1000 = 90 × 1/20
x = 44 × 90 / (1000×20)
x = 0.198 g

Therefore, percentage of oxalate ions in salt
= 0.198 / 0.3 × 100
= 66 %


Hope this helps you...