Find out the percentage purity pure of impure simple of oxalic acid. you are supplied M/100 KMnO4 solution
Answers
Given :- KMnO4 Solution = M/100
To Find :- Percentage purity of impure sample of oxalic acid.
Solution:-
- It is given that the Molarity of Potassium Permanganate is
M(KMnO4) = 1/100
- The balanced chemical equation of potassium permanganate is given below :-
2MnO4(-) + 16H(+) + Cr2O4(2-) ---> 2Mn(2+) + 8H2O + 10CO2
- It is clear from the above balanced equation that 5 moles of oxalic acid is treated with 2 moles of permanganate
- Hence, The Molarity of KMnO4 is:-
Molarity of potassium permanganate = 1/100
volume of Oxalic acid = 20
M(KMnO4) × V(KMnO4)/M(oxalic acid) × V(oxalic acid) = 2/5 ...(i)
- Substitute the value in eq(i)
1/100 × V(KMnO4)/M(oxalic acid) ×20 = 2/5
M(oxalic acid) = x/800
- The strength of oxalic acid is given by the product of Molarity into molar mass
- So, Strength of oxalic acid = Molarity × Molar mass
= x/800 × 126y (g/l)
- Purity of substance can be obtained by dividing the mass of pure chemical by total mass of given sample
- So,The formula is as follow:-
%purity = strength of pure sample/strength of given sample ×100
= y/4 × 100
The percentage purity pure of impure simple of oxalic acid is y/4 × 100
Given:
KMnO₄ Solution = M/100
Step-by-step explanation:
From question, the Molarity of Potassium Permanganate is
M(KMnO₄) = 1/100
The chemical equation of the reaction is given below:
2MnO₄⁽⁻⁾ + 16H⁽⁺⁾ + Cr₂O4⁽²⁻⁾ → 2Mn⁽²⁺⁾ + 8H₂O + 10CO₂
From above reaction, 5 moles of oxalic acid is treated with 2 moles of permanganate.
The Molarity of KMnO₄ is given as:
Molarity of potassium permanganate = 1/100
volume of Oxalic acid = 20
(M(KMnO₄) × V(KMnO₄))/(M(oxalic acid) × V(oxalic acid)) = 2/5 → equation (1)
On substituting the values, we get,
(1/100 × V(KMnO₄))/(M(oxalic acid)) × 20 = 2/5
M(oxalic acid) = x/800
The strength of oxalic acid is given by the product of Molarity into molar mass
⇒ Strength of oxalic acid = Molarity × Molar mass
∴ Strength of oxalic acid = x/800 × 126y (g/l)
The purity of substance can be obtained by dividing the mass of pure chemical by total mass of given sample.
The formula is given as:
⇒ %purity = strength of pure sample/strength of given sample × 100
∴ %purity = y/4 × 100