Question

find out the potential difference if the two resistance 12ohm and 4ohm are connected in series and 4A of current is applied​

Answer 1

Answer:

here

total resistance = 12Ω+4Ω = 16Ω

we know that V = IR

here I = 4A

substituting in the formula

V = 16×4

= 64

so the potential difference is 64Volts

Answer 2

here,

total resistance is= 12 ohm and 4 ohm

= 12+4= 16 ohm

: v=IR

v= 16 x 4

= 64

so potential difference is 64 volt

Explanation:

we add 12 ohm and 4 ohm because in series circuit we always add the resistance,

here's the extra knowledge

in series circuit: resistance is always ad and voltage divide

In parallel circuit: resistance divide and voltage remain same.