Question

Find out the pressure executing on a table top of side 20 cm * 10 cm ,and exerts a force of 10 Kgf
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Answer 1

Answer:

Given :-

Length of the rectangular block = 20 cm

Breadth of the rectangular block = 10 cm

Force applied = 240 N

To Find :-

The pressure exerted by the block on the ground.

Solution :-

We know that,

p = Pressure

f = Force

a = Area

l = Length

b = Breadth

Using the formula,

\underline{\boxed{\sf Area \ of \ the \ rectangle=Length \times Breadth}}Area of the rectangle=Length×Breadth

Given that,

Length (l) = 20 cm

Breadth (b) = 10 cm

Substituting their values,

a = 20 × 10

a = 200 cm²

Using the formula,

\underline{\boxed{\sf Pressure=\dfrac{Force}{Area} }}Pressure=AreaForce

Given that,

Area = 200 cm² = 0.02 m²

Force (f) = 240 N

Substituting their values,

p = 240/0.02

p = 12000 Pa

Therefore, the pressure exerted by the block on the ground is 12000 Pa.