find out the probability of forming 187 or 215 with digits 1,2,3,4,5,6,7,8,9 when only numbers of three digits are formed and when repititions are not allllwed?
Answers
Answered by
17
Answer:
Step-by-step explanation:
The digits are 1 ,2,3,4,5,6,7,8,9
Total 9 digits
(1) Positive outcomes=2(187 or 215)
For repetition not allowed
Total outcomes=9×8×7=504
Required probability=2/504=1/252
For repetition allowed 9×9×9=729
(2) required probability=2/729
Answered by
1
Given; 1,2,3,4,5,6,7,8,9
To find; the probability of forming 187 or 215 with digits 1,2,3,4,5,6,7,8,9 when only numbers of three digits are formed and when repetitions are not allowed
Solution;
the probability of forming 187 or 215 with digits 1,2,3,4,5,6,7,8,9 when only numbers of three digits are formed and when repetitions are not allowed
Total numbers that can be formed = 9×8×7
Given numbers =2
Probability= 1/252
Hence the probability is 1/252
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