Question

Find out the probability of getting 53 fridays and 53 saturdays in a leap year?

Answer 1

Total outcomes =7
(Monday,Tuesday ,Wednesday,Thursday,Friday,Saturday,Sunday)
Favourable outcome of friday=2
P(53 friday)=2/7
Favourable outcome of Saturday=2
P(53 saturday)=2/7

Answer 2

Answer:

1/7

Step-by-step explanation:

A leap contains 366 days

52*7 =364

The other 2 days will be consecutive ie(sunday,monday), (monday,tuesday),( Tuesday, Wednesday)....(friday, saturday), (Saturday, Sunday)

Out of these only one is useful ie friday and saturday

So probability of getting 53 fridays and 53 saturday is 1/7