Question

find out the product of the following pairs of numbers and find factors of the products obtained (a) 8,6 (b) 7,5 (c) 12,9 (d) 14,2​

Answer 1

Answer:

(a) 8,6 = 48 = $2^{4} * 3^{1}$

(b) 7,5 = 35 = $7 * 5$

(c) 12,9 = 108 = $2^{2} * 3^{3}$

(d) 14,2​ = 28 = $2^{2} * 7$

Step-by-step explanation:

To find the factors we take out the prime factors of the products.

factors other than the prime factors are :

(a) 8,6 = 48 = 1 , 2 , 3 , 4 , 6 , 8 , 12 , 16 , 24 , 48

(b) 7,5 = 35 = 5 , 7

(c) 12,9 = 108 = 1 , 2 , 3 , 4 , 6 , 8 , 9 , 12 , 18 , 27 , 36 , 54 , 108

(d) 14,2​ = 28 = 1 , 2 , 4 , 7 , 14 , 28