Question

Find out the smallest number, which divides by 35, 45 and 55 respectively, 17, 27 and 37 remaining?​

Answer 1

Answer: 3447

Explanation:

35-17=45-27=55-37=18

Let m be the required number. Then m+18 will be a multiple of 35, 45 and 55

We need to find the LCM of 35,45,and 55

35=5x7

45=3x3x5

55=5x11

So LCM=5x7x3x3x11=3465

So the required number will be 3465-18=3447