Find out the smallest number, which divides by 35, 45 and 55 respectively, 17, 27 and 37 remaining?
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Answer: 3447
Explanation:
35-17=45-27=55-37=18
Let m be the required number. Then m+18 will be a multiple of 35, 45 and 55
We need to find the LCM of 35,45,and 55
35=5x7
45=3x3x5
55=5x11
So LCM=5x7x3x3x11=3465
So the required number will be 3465-18=3447
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