Math, asked by shob0, 1 year ago

Find out the smallest number, which divides by 35, 45 and 55 respectively, 17, 27 and 37 remaining?​

Answers

Answered by shameemamk
1

Answer: 3447

Explanation:

35-17=45-27=55-37=18

Let m be the required number. Then m+18 will be a multiple of 35, 45 and 55

We need to find the LCM of 35,45,and 55

35=5x7

45=3x3x5

55=5x11

So LCM=5x7x3x3x11=3465

So the required number will be 3465-18=3447

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