find out the smallest number which is divisible by 6, 12, 18
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To find the smallest no. divisible by 6,12,18
You have to find the LCM (Lowest Common Multiple) of 6,12,18 by prime factorisation
6 = 2 x 3
12 = 2 x 3 x 2
18 = 2 x 3 x 3
Common factors of 6,12,18 are 2 and 3
Uncommon factors are 2 and 3
LCM = Common factors x Uncommon factors
= 2 x 3 x 2 x 3
= 36
Therefore, 36 is the smallest number divisible by 6,12 and 18
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