find out the smallest number which on being added 3 to it ,is exactly divisible by 50,90,126and 168.
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We have to find the smallest number which on being added 3 to it ,is exactly divisible by 50,90,126and 168.
So therefore, we have to find the LCM of 50, 90, 126 and 168.
LCM(50, 90, 126, 168) = 12600
the number should be exactly divisible by 50, 90, 126 and 168 when 3 is added to it.
the smallest number divisible by 50, 90, 126 and 168 is 12600
so subtract 3 from 12600
12600-3= 12,597
Therefore, smallest number which on being added 3 to it ,is exactly divisible by 50,90,126and 168 is 12597.
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