Math, asked by kumarikhushbudeo99, 9 months ago

find out the smallest number which on being added 3 to it ,is exactly divisible by 50,90,126and 168.

Answers

Answered by anilkumar180535
1

We have to find the smallest number which on being added 3 to it ,is exactly divisible by 50,90,126and 168.

So therefore, we have to find the LCM of 50, 90, 126 and 168.

LCM(50, 90, 126, 168) = 12600

the number should be exactly divisible by 50, 90, 126 and 168 when 3 is added to it.

the smallest number divisible by 50, 90, 126 and 168 is 12600

so subtract 3 from 12600

12600-3= 12,597

Therefore, smallest number which on being added 3 to it ,is exactly divisible by 50,90,126and 168 is 12597.

hope this helps you

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