find out the solution set and its nature of x +y=0 and (x,y)€z
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since x+y=0
x = - y
and (x,y)€z
x and y may be +ve or -ve
{(-1,1);(-2,2);(-3,3)............(1,-1);(2,-2).........}
x = - y
and (x,y)€z
x and y may be +ve or -ve
{(-1,1);(-2,2);(-3,3)............(1,-1);(2,-2).........}
janibasha16:
I can't understand
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