Question

Find out the sum, for which the difference, between the compound and simple

interest, for 3 years at the rate of 10% per annum, would be ` 31?​

Answer 1

Answer:

1000=p

Step-by-step explanation:

c.i-s.i=31

ci-si=p((1+r/100)^t-1)-p*r*t/100

31=p((1+10/100)^3-1)-p*10*3/100

31=p(110/100)^3-1)-p30/100

31=p(11/10)^3-1)-p30/100

31=p(1331/1000-1-30/100)

31=p(1331-1000-300/1000)

31=p(31/1000)

31*1000/31=p

1000=p