Question

Find out the sum required to earn a monthly interest of Rs. 1200 at 18% P.A. find S.I.

Answer 1

Step-by-step explanation:

= Po*r*t = rupees 1200.

r = (18%/12)/100% = 0.015 = Monthly % rate expressed as a decimal.

t = 1 Mo.

Po*0.015*1 = 1200.

Po = $80,000.

Here,

Nov 10, 2015

SI = P×R×T

------

100

14400(1200×12)=P(?)×18×1

--------

100

14400= 0.18 P

P = 80000

I hope you are satisfied with my Answer ..

Answer 2

Answer:

Rs. 18

Step-by-step explanation:

time = 30 days = 1/12 years

principle = Rs. 1200

Rate of interest = 18%

SI = p * r* t /100

   =1 * 1200 *18/100 * 12

    = rs. 18