Question

find out the summation of the following series:
1+1/4+1/7+1/10​

Answer 1

Answer:

nth term Tn=(3n−2)(3n+1)(3n+4)1

By partial fraction we get

Tn=61[(3n−2)(3n+1)1−(3n+1)(3n+4)1]

T1=61[1.41−4.71]

T2=61[4.71−7.101]

Tn=61[(3n−2)(3n+1)1−(3n+1)(3n+4)1]

Then, Sn=

Answer 2

Step-by-step explanation:

hope it will help all of you...