Find out the surface temperature & total power emitted from the surface of a star, if the radiation emitted by the star has maximum Intensity at wavelength 440 nm.
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Answer:
λmaxT=b
∴T=λmaxb=289.8nm2898μmK
289.8×10−9m2898×10−6mK=104K
According to Stefan Boltzmann law,
Radiation intensity, R=σT4
R=(5.67×10−8Wm−2K−4)(104K)4
=5.67×108Wm−2
Explanation:
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