Question

Find out the total no. Of o atom in 5.3 g of na2co3

Answer 1

qwerr18384v 8- 83' i 8- 2873v82737b 8- 734 - 7377- 7eu2i4o0 SOLVE THIS EQUATION I HOPE YOU WILL FIND YOUR ANSWER

Answer 2

Moles of Na2CO3=5.3/106=0.05

so moles of Na=0.05×2=0.1

moles of C=0.05×1=0.05

moles of O=0.05×3=0.15

we can now find the no. of atoms of each type by multiplying the no. of moles by Avagadro's constant.

I. E. O= 0.15 * 6.023*10^23

=0.90*10^23 atoms

Hope it helps:-)