Question

Find out the value of Kcfor each of the following equilibria from the value of K:
(i) 2NOCI (g) = 2NO (g) + C1, (g); K= 1.8 x 10-2 at 500 K​

Answer 1

Answer:

The relationship between Kp and Kc is Kp=Kc(RT)Δn.

For the reaction 2NOCl(g)⇌2NO(g)+Cl2(g), the value of Δn is 1+2−2=1.

Substituting this value in the above expression, we get

Kp=Kc(RT)Δn=Kc(RT)1.

But KP=1.8×10−2,R=0.082L atm /mol. K,T=500K.

Substituting values in the above expression, we get

1.8×10−2=Kc(0.082×500)1.

Kc=4.4×10−4.

For the reaction CaCO3(s)⇌CaO(s)+CO2(g), the value of Δn is =1.

Substituting this value in the above expression, we get

Kp=Kc(RT)Δn=Kc(RT)1.

But