Math, asked by tejpal12970, 1 month ago

find out the value of one digit
7 the power(95) - 3 power (58)

Answers

Answered by anananan1120
0

Answer:

7^95 - check the last digit pattern:

7^1 = 7

7^2 = 49

7^3 = 343

7^4 = 2401

7^5 = 16807 - the pattern already repeats. It repeats every 5th number exponent. So divide the exponent by 4. If the remainder is:

0 - last digit 1

1 - last digit 7

2 - last digit 9

3 - last digit 3

95 / 4 = 23 remainder 3. The last digit is 3

3^58 - check the last digit pattern.

3^1 = 3

3^2 = 9

3^3 = 27

3^4 = 81

3^5 = 243 It repeats every 5th number exponent. So divide the exponent by 4. If the remainder is:

0 - last digit 1

1 - last digit 3

2 - last digit 9

3 - last digit 7

58 / 4 = 14 R 2. The last digit is 9.

Solve the problem.

7^95 last digit is 3. 3^58 last digit is 9. 3 x 9 = 27. The last digit is 7. That's choice d.

3 x 9 = 27, The last digit is 7.

Answered by syamalanakka08
0

Step-by-step explanation:

7power -5

3 power -8 I hope this will help you

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