Question

Find out the velocity of a ball at the time it reaches the surface of earth,when it is dropped

out from a height of 10 m?​

Answer 1

Answer:

14.1 m/s....

Explanation:

Given, u = 0

a = 10 (consider)

s = 10 m

So, by formulae,

v^2 = u^2 + 2as

v^2 = 0 + 2(10)(10)

v^2 = 200

v = 10* under root 2

v = 10 * 1.41

v = 14.1 m/s

Hope It Helps!!