Question

find out the volume of cl2 at stp produced by the action of 100cm^3 of 0.2n hcl on excess of mno2

Answer 1

Answer:

So, 0.2 N HCl = 0.2M HCl. So, 0.02 mol HCl will produce = 1/4 x0. 02 =0.005 mole of Cl2 gas. so, 0.005 moles of Cl2 gas = 22.4 x 0.005 =0.112 L of Cl2 gas