Question

Find out the volume of cl2 at stp produced by the action of 100 cm3 of 0.2 n hcl in excess of mno2

Answer 1

Answer:

Explanation:

=> 0.2 N HCL is equal to 0.2 moles of H⁺ per Liter of solutions.

As 1 mole of H⁺ ions are equal to 1 mole of HCL,

then 0.2 N HCL = 0.2 M HCL

=> As we know, 1 L (1000 cm³) of the solution contains 0.2 moles of HCL

then 100cm³ of the solution will contains = 0.2 * 1000 * 100

= 0.02 moles of HCL

Now, the reaction is given below

MnO₂ + 4HCL --> MnCl₂ + 2H₂O + Cl₂

According to equation, 4moles of HCL is equals to 1 mole of Cl₂

Thus, 0.02 mol HCL will form = 1/4 * 0.02 = 0.005 mole of Cl₂ gas.

The volume of cl2 at STP :

1 mole of cl₂ gas is equals to 22.4 liters

Thus, 0.005 moles of Cl₂ gas = 22.4 * 0.005

= 0.112 L

Answer 2

0.112 L

Explanation:

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