find out the volume of moles in 56 gram nitrogen at STP
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hey buddy !! here's your answer....
➡️1 mole of N2 = 28 grams = 22.4 L volume is occupied by it
28 g = 1 mole
so,
56 g = 56/28 = 2 moles.
1 mole occupies volume = 22.4 L
so,
2 moles will occupy = 22.4 x 2 = 44.8 L.✔️
hope it helps !!✌️❤️
bonne journée !! ❤️
➡️1 mole of N2 = 28 grams = 22.4 L volume is occupied by it
28 g = 1 mole
so,
56 g = 56/28 = 2 moles.
1 mole occupies volume = 22.4 L
so,
2 moles will occupy = 22.4 x 2 = 44.8 L.✔️
hope it helps !!✌️❤️
bonne journée !! ❤️
tanmay855:
thanks
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