Find out the wavelength of the electron orbiting in the ground state of hydrogen atom
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The wave length of the electron orbiting in the ground state of hydrogen atom because the electron and proton only orbiting in the ground state
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Answer:
3.33*10^-10m
Explanation:
We know E=13.6/n^2
Now here n=1.
Therefore E=13.6* 1.6*10^-19 J
Now
Lambda = h/√2mE
= 6.63* 10^-34/√2 * 9.1*10^-31 *
13.6* 1.6*10^-19
=6.63 * 10^-34/19.9*10-25
=0.3331 * 10^-9 m
=3.33 * 10^-10 m
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