Question

find out the weight of nh3 produced from 56 ml n2 at stp​

Answer 1

Answer:

N

2

+3H

2

⟶2NH

3

Number of moles of N

2

in 140g=

28

140g

=5 moles of N

2

Number of moles of H

2

in 30g=

2

30

=15 moles of H

2

moles N

2

+3H

2

⟶2NH

3

at t=0 5 15 -

after reaction 5−5×1 15−3×5 2×5

Thus 10 moles of NH

3

produced after reaction

as number of moles=

volume at STP

volume of product

⇒10=

22.4L

V

⇒V=224L

Thus 224L of ammonia is produced.

Explanation:

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Answer 2

Explanation:

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