Find out the weight of solute present in 250g of solution with 20% of w/W%
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Answer:Correct option is
A
120g
Relative lowering in vapour pressure=
P
0
P
0
−P
S
=
M
1
×W
2
W
1
×M
2
where 1 & 2 denote solute and solvent respectively.
Given, P
S
=
5
4
P
0
⇒
5
1
=
60×180
W×18
∴W=120g
Step-by-step explanation:
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