Question

Find out the weight of the calcium carbonate that must be decomposed to produce sufficient quantity of carbon dioxide to convert 10.6g of sodium carbonate completely into sodium bi carbonate

Answer 1

Answer:

CaCO3  + H2O +  Na2CO3  →  CaO  +  2NaHCO3  

 Mol. Wt.  100                      106

 

106 gm of Na2CO3  = 100 gm CaCO3

 

Therefore   10.6gm = 100 x 10.6 / 106

                              = 10 gm of CaCO3 is required.

Answer 2

Answer:

10 GM

Explanation:

we require 10 GM of CaCo .