Find out the weight of the calcium carbonate that must be decomposed to produce sufficient quantity of carbon dioxide to convert 10.6g of sodium carbonate completely into sodium bi carbonate
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Answered by
5
Answer:
CaCO3 + H2O + Na2CO3 → CaO + 2NaHCO3
Mol. Wt. 100 106
106 gm of Na2CO3 = 100 gm CaCO3
Therefore 10.6gm = 100 x 10.6 / 106
= 10 gm of CaCO3 is required.
Answered by
2
Answer:
10 GM
Explanation:
we require 10 GM of CaCo .
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