Math, asked by akkimahan, 8 months ago

Find out three numbers lying between
$\frac{2}{3}$
and
$\frac{3}{4}$

Answers

Answered by Battleangel

10

$<body bgcolor="cyan"$

1:-

$\frac{1}{2} \times ( \frac{2}{3} + \frac{3}{4} )$

$= \frac{1}{2} \times ( \frac{2}{3} \times \frac{4}{4} + \frac{3}{4} \times \frac{3}{3} )$

$= \frac{1}{2} \times ( \frac{8}{12} + \frac{9}{12} )$

$= \frac{1 }{2} \times ( \frac{8 + 9}{12} ) \: (as \: denominators \: are \: same)$

$= \frac{1}{2} \times \frac{17}{12}$

$= \frac{17}{24} ...............(i)$

2:-

$= \frac{1}{2} \times (\frac{17}{12} + \frac{3}{4} )$

$= \frac{1}{2} \times ( \frac{17}{24} + \frac{3}{4} \times \frac{6}{6} )$

$= \frac{1}{2} \times ( \frac{17}{24} + \frac{18}{24} )$

$= \frac{1}{2} \times ( \frac{17 + 18}{24} )$

$= \frac{1}{2} \times \frac{35}{24}$

$= \frac{35}{48} ..................(ii)$

3:-

$\frac{1}{2} \times ( \frac{35}{48} + \frac{3}{4})$

$= \frac{1}{2} \times ( \frac{35}{48} + \frac{3}{4} \times \frac{12}{12} )$

$= \frac{1}{2} \times ( \frac{35}{48} + \frac{36}{48} )$

$= \frac{1}{2} \times ( \frac{71}{48} )$

$= \frac{71}{96}.........(iii)$

hope this helps you xD

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