find out velocity of the stone in 3s
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Let,
u = Initial velocity of stone
H = Maximum height attained by the stone
v = final velocity at maximum height = 0
t = time taken to attain maximum height = 3s
a=−g= acceleration due to gravity
(i) We know that,
v=u+at
0=u−g×3
u=3g=3×9.8ms
−2
u=29.4ms
−1
(ii) From the equations of motion , we know that ,
s=ut+
2
1
at
2
H=29.4×3+
2
1
9.8×9
H=88.2+44.1
H=132.3m
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