Find out whether the points (1,5) (2,5) and(-2,-1)are collinear using the distance formula.
Answers
Answer:
A(1,5);B(2,5);C(-2,-1)
A=(1, 5),B=(2,5)
AB=Underroot (x2-x1)²+(y2-y1) ²
=Underroot (2-1)²+(5-5)
= (1)²+(0)²
= 1+0
= 1unit
B=(2,5),C=(-2,-1)
BA=Underroot (x2-x1)²+(y2-y1)²
= (-2-2)²+(-1-5)²
= (-4)²+(-6)²
= 16+36
= 52units
C=(-2,-1),A=(1,5)
CA=Underroot (x2-x1)²+(y2-y1)²
= (1-(-2))²+(5-(-1))²
= (3)²+(6)²
= 9+36
= 45units
Step-by-step explanation:
Where I wrote Underroot nd left space there u have to keep root bcoz in the keyboard the sign of root is not keep given.
It is fully correct nd me also of class 10th nd this question was there....
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