Question

find out whether x²-√2x-4=0 is the solution of the x=-2√2 or not​

Answer 1

Step-by-step explanation:

$x = 2 \sqrt{2}$

${x}^{2} - \sqrt{2} x - 4 = 0$

$({2 \sqrt{2}) }^{2} - (\sqrt{2} \times 2 \sqrt{2} ) - 4$

$8 - 4 - 4 = 0$

$8 - 8 = 0$

HENCE IT IS A SOLUTION

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Answer 2

Step-by-step explanation:

put x = -2√2 in the given polynomial and if it becomes zero, then x = -2√2 is a solution

let p(x) = x² - √2x - 4

then p (-2√2) = (-2√2)² - √2 * (-2√2) - 4

=> 8 + 4 - 4

=> 8 ≠ 0

hence x = - 2√2 is not a solution