Question

find out which of the following are irrational numbers :- (i) 6√5 (ii) 7 (iii) √5+√3 ​

Answer 1

Answer:

6√5 and √5+√3 are irrational.

Hope it helps u.

Answer 2

$\underline { \blue { Irrational \: numbers :}}$

A number which cannot be expressed as a terminating decimal or a repeating decimal is called an Irrational number .

$Here,\blue { i ) 6\sqrt{5} \: and \: iii ) \sqrt{5} +\sqrt{3}}\\are \: irrational \: numbers$

$\underline { \pink { Rational \: number :}}$

$A \: number \: which \:can \:be \: written \: in \\the \:form \:of \: \frac{p}{q} , \:where \: p \:and \:q \\are \: integers \:and \: q \neq 0 \:is \: called \: a \\Rational \: number$

$Here, \pink{7} \:is \:a \: rational \: number .$

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