Find out which operation must be done on both sides of these equations in order to solve them. 1.x+9=11,2.x-4=9,3.8x=24 and x/6=3
Answers
Solution
First to find the value of x we need to eliminate constants in LHS
To eliminate x :
→ If in LHS addition ( + ) opertion is there between constant and variable, then subtraction operation should be done on both sides to solve x + 9 = 11
And 9 i.e constant in LHS only should be subtracted on both sides.
Solving x + 9 = 11
Subtracting 9 on both sides
To eliminate x :
→ If in LHS subtraction ( - ) opertion is there between constant and variable, then addition operation should be done on both sides to solve x + 4 = 9
And 4 i.e constant in LHS only should be added on both sides.
Solving x - 4 = 9
Adding 4 on both sides
To eliminate x :
→ If in LHS multiplication ( * ) opertion is there between constant and variable, then division operation should be done on both sides to solve 8x = 24
And 8 i.e constant in LHS only should be divided on both sides.
Solving 8x = 24
Dividing 8 on both sides
To eliminate x :
→ If in LHS division ( / ) opertion is there between constant and variable, multiplication operation should be done on both sides to solve x/6 = 3
And 6 i.e constant in LHS only should be multiplied on both sides.
Solving x/6 = 6
Mutiplying by 6 on both sides
Question :-
Given above ↑
Answer :-
(1) x = 2
(2) x = 13
(3) x = 3
(4) x = 18
Explanation for each question :-
(1) x + 9 = 11
For eliminating 9 which is with "x" subtract 9 on both sides,
→ x + 9 - 9 = 11 - 9
→ x = 2
__________________________
(2) x - 4 = 9
Adding 4 on both sides ,
→ x - 4 + 4 = 9 + 4
→ x = 13
__________________________
(3) 8x = 24
Divided by 8 on both sides ,
→ 8x/8 = 24/8
→ x = 3
__________________________
(4) x/6 = 3
multiplying by 6 on both sides ,
→ 6 • x/6 = 6 • 3
→ x = 18
__________________________
Hope it helps you : )