Math, asked by prabhakarbharati6, 10 months ago

Find out which operation must be done on both sides of these equations in order to solve them. 1.x+9=11,2.x-4=9,3.8x=24 and x/6=3​

Attachments:

Answers

Answered by Anonymous
44

Solution

 \tt (1)x  +   9 = 11

First to find the value of x we need to eliminate constants in LHS

To eliminate x :

→ If in LHS addition ( + ) opertion is there between constant and variable, then subtraction operation should be done on both sides to solve x + 9 = 11

And 9 i.e constant in LHS only should be subtracted on both sides.

Solving x + 9 = 11

 \implies x  +   9 = 11

Subtracting 9 on both sides

 \implies  \boxed{x  = 2}

 \tt (2)x - 4 = 9

To eliminate x :

→ If in LHS subtraction ( - ) opertion is there between constant and variable, then addition operation should be done on both sides to solve x + 4 = 9

And 4 i.e constant in LHS only should be added on both sides.

Solving x - 4 = 9

 \implies x   -    4 = 9

Adding 4 on both sides

 \implies x   -    4  + 4= 9 + 4

 \implies  \boxed{x =13}

 \tt (3)8x = 24

To eliminate x :

→ If in LHS multiplication ( * ) opertion is there between constant and variable, then division operation should be done on both sides to solve 8x = 24

And 8 i.e constant in LHS only should be divided on both sides.

Solving 8x = 24

 \implies 8x = 24

Dividing 8 on both sides

 \implies  \dfrac{8x}{8}  =  \dfrac{24}{8}

 \implies   \boxed{x  =  3}

 \tt (4) \dfrac{x}{6}  = 3

To eliminate x :

→ If in LHS division ( / ) opertion is there between constant and variable, multiplication operation should be done on both sides to solve x/6 = 3

And 6 i.e constant in LHS only should be multiplied on both sides.

Solving x/6 = 6

 \implies  \dfrac{x}{6}  = 3

Mutiplying by 6 on both sides

 \implies  \dfrac{x}{6} \times 6  = 3 \times 6

 \implies  \boxed{x = 18}

Answered by Sharad001
179

Question :-

Given above ↑

Answer :-

(1) x = 2

(2) x = 13

(3) x = 3

(4) x = 18

Explanation for each question :-

(1) x + 9 = 11

For eliminating 9 which is with "x" subtract 9 on both sides,

→ x + 9 - 9 = 11 - 9

→ x = 2

__________________________

(2) x - 4 = 9

Adding 4 on both sides ,

→ x - 4 + 4 = 9 + 4

→ x = 13

__________________________

(3) 8x = 24

Divided by 8 on both sides ,

→ 8x/8 = 24/8

→ x = 3

__________________________

(4) x/6 = 3

multiplying by 6 on both sides ,

→ 6 • x/6 = 6 • 3

→ x = 18

__________________________

Hope it helps you : )

Similar questions