Question

find out which operations must be done on both side of this question in order to solve them 1) x÷10=5

please answer it......​

Answer 1

Answer:

50

Step-by-step explanation:

x÷10=5

x=5×10=50

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Answer 2

${\huge{\boxed{\sf{\green{Question}}}}}$

Find out which operations must be done on both side of this question in order to solve them 1) x÷10=5

${\huge{\boxed{\sf{\green{Answer}}}}}$

$\tt (1)x + 9 = 11$

First to find the value of x we need to eliminate constants in LHS

To eliminate x :

→ If in LHS addition ( + ) opertion is there between constant and variable, then subtraction operation should be done on both sides to solve x + 9 = 11

And 9 i.e constant in LHS only should be subtracted on both sides.

Solving x + 9 = 11

$\implies x + 9 = 11$

Subtracting 9 on both sides

$x=2$

$(2) x-4=9$

To eliminate x :

→ If in LHS subtraction ( - ) opertion is there between constant and variable, then addition operation should be done on both sides to solve x + 4 = 9

And 4 i.e constant in LHS only should be added on both sides.

Solving x - 4 = 9

$=x - 4 = 9$

Adding 4 on both sides

$\implies x - 4 + 4= 9 + 4$

$\implies \boxed{x =13}$

$\tt (3)8x = 24$

To eliminate x :

→ If in LHS multiplication ( * ) opertion is there between constant and variable, then division operation should be done on both sides to solve 8x = 24

And 8 i.e constant in LHS only should be divided on both sides.

Solving 8x = 24

$\implies 8x = 24$

Dividing 8 on both sides

$\implies \dfrac{8x}{8} = \dfrac {24}{8}$

$\implies \boxed{x = 3}$

$\tt (4) \dfrac{x}{6} = 3$

To eliminate x :

→ If in LHS division ( / ) opertion is there between constant and variable, multiplication operation should be done on both sides to solve x/6 = 3

And 6 i.e constant in LHS only should be multiplied on both sides.

Solving x/6 = 6

$\implies \dfrac{x}{6} = 3$

Mutiplying by 6 on both sides

$\implies \dfrac{x}{6} \times 6 = 3 \times 6$

$\implies \boxed{x = 18}$

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