Question

find out............ with a smile...

Answer 1

b^2 - 4ac = 0 where
a=
$13 \times \sqrt{3}$
b= 10

and c =
$\sqrt{3}$

Answer 2

nature of roots

$a = 13 \sqrt{3} \\ b = 10 \\ c = \sqrt{3}$

$b {}^{2} - 4ac \: \\ (10) {}^{2} - 4(13 \sqrt{3} )( \sqrt{3} ) \\ 100 - 156 \\ - 56 <0$

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