Question

find out x and y in this question....

Answer 1

According to question,

AB = AE

And, CF = DF

=> 13x - 50 = 20 - 11y

=> 13x + 11y = 70

=> 143x + 121y = 770 ------(1)

And,

13y - 24 = 50 - 11x

=> 11x + 13y = 74

=> 143x + 169y = 962 ------(2)

On subtracting equation 1 from 2, we get

48y = 192

=> y = 4

Now,

On putting the value of y in equation 1, we get

13x + 11 (4) = 70

=> 13x + 44 = 70

=> 13x = 26

=> x = 2

Answer 2

Given that AB = AE

So, 13x - 50 = 20 - 11y

=> 13x - 50 = 20 - 11y

=> 13 x + 11y = 20 + 50

=> 13x + 11y = 70 ------1equation


×××××××××××××××××××

Also, CF = FD

So, 13y - 24 = 50 - 11x

13y + 11x = 50 + 24

13y + 11x = 74 ----_2equation


××××××××××××××××××××

[ 13x + 11y = 70] × 11
[ 11x + 13y = 74] × 13

××××××××××××××××××××

143x + 121y = 770
143x + 169y = 962
(-)__(-)____(-)___
48y = 192
_____________

$y = \frac{192}{48} \\ \\ y = 4$


Putting the value of y in 1equation,


13x + 11y = 70

13x + 11(4) = 70

13x + 44 = 70

13x = 70 - 44

13x = 26

$x = \frac{26}{13} \\ \\ x = 2$





I hope this will help you



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