Find Out Y2 :
Y=log(ax+x2)
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if you are asking y" = ? ( because y" or d²y/dx² or y2 is same )
solution:-
y = log(ax + x²)
dy/dx = 1/(ax + x²).d(ax + x²)/dx
= (a + 2x)/(ax + x²)
but when you are saying y² = ?
then, y = log(ax + x²)
y² = {log(ax + x²)}²
solution:-
y = log(ax + x²)
dy/dx = 1/(ax + x²).d(ax + x²)/dx
= (a + 2x)/(ax + x²)
but when you are saying y² = ?
then, y = log(ax + x²)
y² = {log(ax + x²)}²
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