Question

find Oxidation no. of all the elements in Pbso4....​

Answer 1

Pbso4

total number of different element = 3

all different elements are

lead oxidation state +2

sulphur oxidation state -2

Oxygen oxydation state -2

Now

in Pbso4

suppose oxydation state of pb is x

x -2 -8 = 0

x = 10

so oxidation state of sulphur is +10

for s

let oxydation state of s in Pbso4 is

+2 +x - 8= 0

x = 6

so sulphur oxidation number is + 6

for oxygen

late oxidation number of oxygen be x

4x - 2 + 2=0

x =0