Question

Find oxidation number of cr in CrO4 2-

Answer 1

Hey!!!

oxidation no. of Cr is..

=> x+ ( -2 × 4 ) = -2

=> x = + 6

So, oxidation state of Cr is +6.

Answer 2

Answer: The oxidation number of chromium in the given compound is +6

Explanation:

Oxidation number is defined as the number which is assigned to the element when it gains or loose electrons. If the element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

We are given a chemical compound having formula of $CrO_4^{2-}$

We take the oxidation state of chromium atom be 'x'.

Oxidation state of oxygen atom = -2

Evaluating the oxidation state of chlorine atom:

$x+4(-2)=-2\\\\x=+6$

Hence, the oxidation number of chromium in the given compound is +6.