Question

find oxidation number of N in (N2H5)2SO4

Answer 1

The oxidation number of nitrogen in the molecule is equal to-2

Explanation

• The oxidation number for sulphate ion , SO4 is equal to - 2.

• So, the oxidation number of two ion N2H5 will be 2

• Or, the oxidation number of the ion N2H5 will be 2/2 = 1 . [This is due to the nature of the molecule which is neutral in nature.]

• The oxidation number of hydrogen is equal to +1.

Let us consider the oxidation number of nitrogen be x.

• 2x + (5x1) = 1
• ⇒2x= -4
• ⇒x= -4/2= -2

• Hence  oxidation number of nitrogen in the given compound is equal to-2

To know more about oxidation number,

Oxidation number of An in HAuCl4 - Brainly.in

https://brainly.in/question/2405432

Answer 2

Answer:

answer is-2 and it might be -2.5 also