Question

Find oxidation state of 1.[Co(Nh3)6]Cl3,2.Co(Nh3)3Cl3],3.[Co(Nh3)4Cl]So4​

Answer 1

answer;Let X be the oxidation number of metal in the complex.

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3(ii) X+2(−1)+2(0)=+1

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3(ii) X+2(−1)+2(0)=+1X=+3

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3(ii) X+2(−1)+2(0)=+1X=+3(iii) X+4(−1)=−2

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3(ii) X+2(−1)+2(0)=+1X=+3(iii) X+4(−1)=−2X=+2

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3(ii) X+2(−1)+2(0)=+1X=+3(iii) X+4(−1)=−2X=+2(iv) 3(+1)+X+6(−1)=0

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3(ii) X+2(−1)+2(0)=+1X=+3(iii) X+4(−1)=−2X=+2(iv) 3(+1)+X+6(−1)=0X=+3

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3(ii) X+2(−1)+2(0)=+1X=+3(iii) X+4(−1)=−2X=+2(iv) 3(+1)+X+6(−1)=0X=+3(v) X+3(0)+3(−1)=0

Let X be the oxidation number of metal in the complex.(i) X+0+(−1)+2(0)=+2X=+3(ii) X+2(−1)+2(0)=+1X=+3(iii) X+4(−1)=−2X=+2(iv) 3(+1)+X+6(−1)=0X=+3(v) X+3(0)+3(−1)=0X=+3

I hope this answer helpful for you

✌️ ABHINAV THE INDIAN ✌️

Answer 2

Answer: this isn't an answer but, u think u can fix your answer on my question please the mediums ain't text and audio there right on the question, Article and interactive are the mediums, thank you

Explanation: