Question

find p(0),(1), p(2) for p(y)=y²+y+1​

Answer 1

Answer:

p(0)=1

p(1)=1+1+1=3

p(2)=4+2+1=7

Answer 2

Answer:

p(0)= 0+0+1=1

p(2)=4+2+1=7

p(1)= 1+1+1=3