Question

Find p(0) and p(1) for p(t)= 2 + t + 2t2– 3​

Answer 1

Answer:

p(0) = 2+0+2(0)2-3

p(0 ) = 2+0+0-3

p(0) = -1

p(1) = 2+1+2(1)2-3

p(1) = 2+1+4-3

p(1) = 4

Step-by-step explanation:

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Answer 2

Answer:

Find p(0) and p(1) for p(t)= 2 + t + 2t2– 3

Step-by-step explanation:

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